How many y-intercepts does the graph of the parabola x = -y^2 + 4y - 4 - 2y + 7 have?
Set \(x = 0\) and simplify the equation: \(0 = -y^2 + 2y + 3\)
We can solve for the number of solutions with the discriminant(\(b^2 - 4ac\))
Note that the discriminant is \(2^2 - 4 \times 3 \times -1 = 16\). Because the discriminant is positive, it will have exactly \(\color{brown}\boxed{2}\) y-intercepts.
Set \(x = 0\) and simplify the equation: \(0 = -y^2 + 2y + 3\)
We can solve for the number of solutions with the discriminant(\(b^2 - 4ac\))
Note that the discriminant is \(2^2 - 4 \times 3 \times -1 = 16\). Because the discriminant is positive, it will have exactly \(\color{brown}\boxed{2}\) y-intercepts.