Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (-1,-1). Express your answer in the form "ax^2 + bx + c".
+37159 Vertex (2,4) form of the parabola will be
y = a (x-2)^2 + 4 Now sub in the given point to calulate 'a'
-1 = a(-1-2)^2 + 4
a = -5/9
So your parabola is now
y = -5/9 (x-2)^2 + 4 expand to
y = - 5/9 x^2 + 20/9 x -20/9 + 4 simplify to get the requested form.....
