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Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (-1,-1). Express your answer in the form "ax^2 + bx + c".

 Jul 25, 2021
 #1
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Vertex  (2,4) form of the parabola will be

 

y = a (x-2)^2 + 4          Now sub in the given point to calulate 'a'

-1 = a(-1-2)^2 + 4

a = -5/9

 

So your parabola is now  

  y = -5/9 (x-2)^2 + 4        expand to

           y = - 5/9 x^2 +  20/9 x  -20/9 + 4     simplify to get the requested form.....

 Jul 25, 2021
edited by ElectricPavlov  Jul 25, 2021
edited by ElectricPavlov  Jul 25, 2021

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