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The equation of a parabola is given. y=3/4*x^2−16x+15 What are the coordinates of the vertex of the parabola?

 Jul 31, 2021
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y=3/4*x^2−16x+15     re - arrange to 'vertex form' for a parabola

y = 3/4 (x^2 - 21 1/3 ) + 15               complete the square for 'x'

y = 3/4 ( x- 32/3)^2 - 70 1/3             now you can see the vertex (h,k) = ( 10 2/3, - 70 1/3)

 Jul 31, 2021

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