The equation of a parabola is given. y=3/4*x^2−16x+15 What are the coordinates of the vertex of the parabola?
+36916 y=3/4*x^2−16x+15 re - arrange to 'vertex form' for a parabola
y = 3/4 (x^2 - 21 1/3 ) + 15 complete the square for 'x'
y = 3/4 ( x- 32/3)^2 - 70 1/3 now you can see the vertex (h,k) = ( 10 2/3, - 70 1/3)
