Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (1,-11). Express your answer in the form "ax^2+bx+c".
+2401 A parabola with a vertex of (2, 4) with a vertical axis of symmetry can be written in the form a(x-2)^2 + 4.
Since the parabola contains the point (1, -11) -11 = a(1-2)^2 + 4.
Solve for a and expand the equation for equation of the parabola.
I hope this was helpeful. :))
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