+0  
 
0
84
1
avatar

Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (1,-11). Express your answer in the form "ax^2+bx+c".

 Feb 5, 2022
 #1
avatar+2401 
0

A parabola with a vertex of (2, 4) with a vertical axis of symmetry can be written in the form a(x-2)^2 + 4.

Since the parabola contains the point (1, -11) -11 = a(1-2)^2 + 4.

Solve for a and expand the equation for equation of the parabola. 

 

I hope this was helpeful. :))

 

=^._.^=

 Feb 5, 2022

24 Online Users