+0

# Parrel lines i have no idea what this is

0
156
1

Write an equation of the line that passes through (−4,−1)(−4,−1) and is perpendicular to the line y=43x+6

Guest Oct 30, 2017

#1
+6959
+2

The slope of the line  y = 43x + 6  is  43 .

The slope of a line perpendicular to that is  -1/43

So we want the equation of a line with a slope of  -1/43

that passes through  (-4, -1)  and a general point,  (x, y)

$$\text{slope}\,=\,\frac{y_2-y_1}{x_2-x_1} \\~\\ -\frac{1}{43}=\frac{y-(-1)}{x-(-4)} \\~\\ -\frac{1}{43}=\frac{y+1}{x+4} \\~\\ (-\frac{1}{43})(x+4)=y+1 \\~\\ -\frac1{43}x-\frac4{43}=y+1 \\~\\ -\frac1{43}x-\frac4{43}-\frac{43}{43}=y \\~\\ y=-\frac1{43}x-\frac{47}{43}$$

hectictar  Oct 30, 2017
Sort:

#1
+6959
+2

The slope of the line  y = 43x + 6  is  43 .

The slope of a line perpendicular to that is  -1/43

So we want the equation of a line with a slope of  -1/43

that passes through  (-4, -1)  and a general point,  (x, y)

$$\text{slope}\,=\,\frac{y_2-y_1}{x_2-x_1} \\~\\ -\frac{1}{43}=\frac{y-(-1)}{x-(-4)} \\~\\ -\frac{1}{43}=\frac{y+1}{x+4} \\~\\ (-\frac{1}{43})(x+4)=y+1 \\~\\ -\frac1{43}x-\frac4{43}=y+1 \\~\\ -\frac1{43}x-\frac4{43}-\frac{43}{43}=y \\~\\ y=-\frac1{43}x-\frac{47}{43}$$

hectictar  Oct 30, 2017

### 27 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details