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A 35.4 kg crate is at rest on a level floor, and the coefficient of kinetic friction is 0.323. The acceleration of gravity is 9.8 m/s^2. If the crate is pushed horizontally with a force of 186.012 N, how far does it move in 5.11 s? Answer in units of m.

 Jun 13, 2021
 #1
avatar+32741 
+3

As follows:

 

 Jun 13, 2021
 #2
avatar+35066 
+1

Another way w/out calculus

 

Normal force =  9.81 m/s^2 * 35.4 kg

    frictional force = friction coefficient * normal force =   .323 * ( 9.81 * 35.4)

        net force on object = 186.012  -  .323*(9.81*35.4) = 73.84 N

 

F = ma

73.84  = 35.4 * a       a = 2.086 m/s^2

 

x = x0 + v0 t + 1/2 a t^2

  = 0   +   0    + 1/2 (2.086)(5.11^2) =  27 .23 meters

 Jun 13, 2021

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