In 3Ca(OH)2 + 2 H3PO4 -> Ca3(PO4)2 + 6 H2O, find the percent yield if 31.6 g of calcium hydroxide produces 39.7 g of calcium phosphate.
To find percent yield, we need to divide gotten value (39.7g of Ca3(PO4)2) by the theoretical yield.
To find Theoretical yield:
31.6g of Ca(OH)2 = roughly 0.42625... moles (divide by the average molar mass of Ca(OH)2 of 74.10g/mol)
For every 3 mol of Ca(OH)2, we should get 1 mol of Ca3(PO4)2 so if we divide 0.426... by 3 and multiply it by 1 we get how many moles of Ca3(PO4)2 we should theoretically get: roughly 0.14215... moles
We can then convert this back to grams by multiplying it by Ca3(PO4)2's molar mass of 310.18g/mol to get a theoretical yield of 44.09g
39.7g/44.09g * 100% = 90.04%