My street hockey team plays three games each week. My team lost all 12 games in the first four weeks. Then, my team won two games and lost one game in the fifth week, bringing our record to 2 wins and 13 losses. Each week after that, my team won two games and lost one game. My team first wins at least 80% of its games by the end of n weeks. What is n?
+67 Answer:
At the end of the 10 th week
Step-by-step explanation:
My team plays 3 games and lost all of them (12 $ ) in the first 4 week
so in 4 weeks my team lost 12 $ and all the games
Then total games in three weeks is 4 * 3 = 12
Total lost 12$ then we have a one dolar bet
In the 5th week my team wins 2$ ( two games ) and at the end of 5th week record is:
From 15 games my team won 2 games and lost 13 games and from that on, my team always wins 2 games then:
Let call x number of week after the 5th then
2 + 2*x / 15 + x = 0,6 0,6 = 60 %
Solving for x
2 + 2*x = 0,6 * ( 15 + x )
2 + 2*x = 9 + 0,6 *x
2*x - 0,6*x = 9 - 2
2*x - 0,6*x = 7
1,4*x = 7
x = 7/1,4
x = 5 weks later
Then the answer is 10 weeks
Techno the p*g,
I hope this was helpful
