+0

# Percent

0
132
3

Pizzas are sized by diameter. What percent increase in area results if Chantel's pizza increases from an 8-inch pizza to a 12-inch pizza?

Jul 5, 2022

#1
+2602
0

Original pizza: $$4 ^2 \pi = 16 \pi$$

New pizza: $$6^2 \pi = 36 \pi$$

So, $$36 \div 16 = 2.25 = 225\text{%}$$. But, recall that we are looking for the increase, so we subtract 100, to find that it is a $$\color{brown}\boxed{125 \text{%}}$$ increase.

Jul 5, 2022
#3
+1158
+7

my answer shows an easier way for the percentage step. but still. same answer!

nerdiest  Jul 5, 2022
#2
+1158
+9

An 8-inch pizza has a radius of 4 inches.

A 12-inch pizza has a radius of 6 inches.

Area of first pizza: $$\pi r^2$$$$= 16\pi$$

Area of second pizza: $$\pi r^2=36\pi$$

Calculation of percentage: $$\frac{36-16}{16} \times 100 = 125%$$%

Therefore, the area is increased by $$125$$%

Jul 5, 2022