Class X has 50% more students than Class Y. Class X has 40% fewer students than Class Z. Given that there are 80 students in the 3 classes, how many students are there in Class X?
+100 x=3y/2 x=3z/5 z=15y/6=5y/2
y+3y/2+5y/2=10y/2=5y y=16
x=24 z=40
40+24+16=80
x=24
+36915 x = 1.5 y or y = 2/3 x
x = .6z or z = 1 2/3 x
x summed, the red equations = 80
2/3 x + 1 2/3 x + x = 80
3 1/3 x = 80
x = 24 sudents
