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If the volume of water in the tank at the time is Vt then wouldn't it just be 0?

 Nov 25, 2019
 #1
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+1

We have the equation :

 

Vt  =  V0kt   where V0  = 3000 = the original volume  and t is the number of hours

 

So....when t  = 2 we have

 

2881.2  =  3000k2         divide both sides by   3000

 

2881.2 / 3000  = k2        take the square root of both sides

 

0.98  =  k

 

This means  that every hour after V0, the tanks loses   1 - .98   = .02   = 2% of its water from the previous hour

 

So

 

k = 0.98    and  x  = 2%

 

 

cool cool cool

 Nov 25, 2019

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