+0  
 
0
82
2
avatar

The measure of one of the smaller base angles of an isosceles trapezoid is $60^\circ$. The shorter base is 5 inches long and the altitude is $2 \sqrt{3}$ inches long. What is the number of inches in the perimeter of the trapezoid?

 Jun 22, 2021
 #1
avatar
+1

The answer is 22, it's easy to figure out of you know about 30 60 90 triangles and im too lazy to write the work

 Jun 22, 2021
 #2
avatar+121048 
+1

Let  the  shorter base  be  at the top of the trapezoid

 

If we  draw  a perpendicular  from   the  top right vertex to  the longer  base....we will form a 30-60-90  right  triangle

 

The  altitude  =  2sqt 3

The  right side of the  trapezoid  =   2sqrt (3)  * 2/sqrt( 3 )   =    4

And  remaining side =   2 =    (longer base - shorter base)  / 2

 

The perimeter is

 

Top base  +  2 (sides)  + [ longer base  ]

 

5  +  2(4)   +   [ 5   +   2 (2)   ]     = 

 

22

 

cool cool cool   

 Jun 22, 2021

41 Online Users

avatar