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2250
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Forty-eight congruent parallelograms with sides of length 62 feet and 20 feet are placed in a chevron pattern forming hexagon $ABCDEF$, as shown. What is the perimeter of hexagon $\allowbreak ABCDEF$?

 Apr 6, 2020
 #1
avatar+934 
+4

Based on the information given, there are 24 parallelograms on top and 24 on bottom, that makes 48 sides with a length of 20 feet. There are also four sides with a length of 62 feet. So your answer is 48*20+4*62= 1208 feet.

 

Hope it helps!

 Apr 6, 2020
 #2
avatar+385 
+1

i believe that is right thank u

Paresh  Apr 6, 2020
 #3
avatar+934 
+1

And sorry, I won't be able to answer any more of your questions today, I'm wrapping up for today.

 Apr 6, 2020
 #4
avatar+385 
+1

its ok i already appreciate what u have done for me today

Paresh  Apr 6, 2020

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