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a box contains 12 black and 8 green marbles. In how many ways can three black and two green be picked?! it gave me a hint : this is both a combination and counting principle question.
PLEASE HELP!!!!!
 May 14, 2012
 #1
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It would take a while to explain, but it is 588. Tell every to look at the question "i fun fact". You look at it as well.
 May 17, 2012
 #2
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for black:
tkhan:

In how many ways can three black

and
tkhan:

a box contains 12 black


that's 3 out of 12.

do you already know nCr (from n choose r)? nCr = n! / r!*(n-r)!
[input]n=12; r=3; n! / (r!*(n-r)!)[/input]
[input]ncr( 12, 3)[/input]

for green:
tkhan:

two green be picked


and
tkhan:

and 8 green marbles


that's 2 out of 8.
[input]ncr( 8, 2)[/input]

combinations combined (multiplied):
[input]ncr( 12, 3) * ncr( 8, 2)[/input]
 May 18, 2012

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