Permutation or Combination?

In how many ways that the 5 students can get out in the building with 8 exits? (Should I use permutation or combination?)

Neither

8*8*8*8*8 = 8^5

Each student has 8 exit possibilities.

8^5 = 32768

Label the exits as A,B,C,D,E,F,G,H

Then.....this just consists of choosing all possible combinations of any of the five exits out of the eight.....

And   8C5 = 56 different ways

^Thanks :)

But Chris

You have assumed that they all leave by different exits.

Why would you assume that?

CPhill: There are 5 kids and each one has a choice of 8 exits!!. That makes 8 x 8 x 8 x 8 x 8=8^5