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Each of the digits 1, 2, 3, 4, 5, 6 is used exactly once in forming the 3-digit integers X and Y. How many possible values of X+Y are there if\(|X-Y|=111? \)

 Apr 13, 2023
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6 C 3 ==20 combinations. Divide them by 2 and you will have: 10 pairs of X + Y

 

6 P 3 ==120 permutations. Same as above.

 Apr 13, 2023

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