A ball is thrown horizontally from the top of a building 36.7 m high. The ball strikes the ground at a point 91.9 m from the base of the building. Find the y component of its velocity just before it strikes the ground.
+36916 Thrown horizontally....how long before it his the ground?
x = x0 + vi t+ 1/2 a t2 x = 0 xo = 36.7 m vi =0 a = -9.81 m/s2
0=36.7 + 1/2 (-9.81) t2 solve for t = 2.735 seconds
vf = vo + at
vf = 0 -9.81(2.735) = -26.83 m/s (negative because it is in downward direction) if ya just want the magnitude: 26.83 m/s
+36916 Thrown horizontally....how long before it his the ground?
x = x0 + vi t+ 1/2 a t2 x = 0 xo = 36.7 m vi =0 a = -9.81 m/s2
0=36.7 + 1/2 (-9.81) t2 solve for t = 2.735 seconds
vf = vo + at
vf = 0 -9.81(2.735) = -26.83 m/s (negative because it is in downward direction) if ya just want the magnitude: 26.83 m/s
