A ball is thrown horizontally from the top of a building 36.7 m high. The ball strikes the ground at a point 91.9 m from the base of the building. Find the y component of its velocity just before it strikes the ground.

Guest Oct 29, 2019

#1**+2 **

Thrown horizontally....how long before it his the ground?

x = x_{0} + v_{i} t+ 1/2 a t^{2} x = 0 xo = 36.7 m vi =0 a = -9.81 m/s^{2}

0=36.7 + 1/2 (-9.81) t^{2 }solve for t = 2.735 seconds

v_{f }= vo + at

v_{f} = 0 -9.81(2.735) = -26.83 m/s (negative because it is in downward direction) if ya just want the magnitude: 26.83 m/s

ElectricPavlov Oct 29, 2019

#1**+2 **

Best Answer

Thrown horizontally....how long before it his the ground?

x = x_{0} + v_{i} t+ 1/2 a t^{2} x = 0 xo = 36.7 m vi =0 a = -9.81 m/s^{2}

0=36.7 + 1/2 (-9.81) t^{2 }solve for t = 2.735 seconds

v_{f }= vo + at

v_{f} = 0 -9.81(2.735) = -26.83 m/s (negative because it is in downward direction) if ya just want the magnitude: 26.83 m/s

ElectricPavlov Oct 29, 2019