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Water is being pushed through a pipe that has a 5 cm diameter at a rate of 2.0 cm/s . The pipe then enters a constriction as goes down to a smaller pipe of 3.0 cm in diameter. How fast is the water moving in the smaller pipe?

A.50 cm/s

B.6.0 cm/s

C.22 cm/s

D.5.6 cm/s

 Jul 21, 2016
 #2
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which answer is it then?

 Jul 21, 2016
 #4
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You do the calculation!

Alan  Jul 21, 2016
 #3
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In 1 second a volume pi*(5^2/4)*2 cm^3 approaches the constriction.

In 1 second a volume pi*(3^2/4)*v cm3 leaves the constriction, where v is the speed

, in cm/s, of the water in the smaller pipe.

 

Equate the two volumes and rearrange to find v.

 

.

 Jul 21, 2016
 #6
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Solve for v:
(25 pi)/2 = (9 pi v)/4

 

(25 pi)/2 = (9 pi v)/4 is equivalent to (9 pi v)/4 = (25 pi)/2:
(9 pi v)/4 = (25 pi)/2

 

Divide both sides by (9 pi)/4:
Answer: | v = 50/9=5.56 cm/s. The answer is "D"

 Jul 21, 2016

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