The first meters of a 100 meter dash are covered in 2 seconds. The sprinter accelerated from rest with a constant acceleration. The remaining 90 m are with the sprinters velocity after the the 2 seconds.

1) what was his acceleration?

for this in class we went over it and talked something about **X = Va * t but solving that => 10=Va * 2,** The velocuty turns into **5m/s** so whats the accelration?

2) find the velocity after the first 2 seconds.

I believe that the answer is **5m/s**

3) How long does it take the runner to finish the race.

** No idea in notes i just wrote "2s for 10m/s 90m left. 9+2 =11s" Idk where i got the 10m/s from**

4) Graph the race

** A curve from the origin to 10m and 2s then have a straight line up to 100 and 11s**

BLANK Sep 12, 2019

#1**+2 **

Acceleration = change in velocity / change in time

xf = x0 + v0t + 1/2 a t^2 x 0 = 0 v0 = 0 xf=10 x0= original position or start v0 = original velocity at start xf = final position (10m)

10 = 1/2 a (t^2)

10 = 1/2 a (2^2)

20/4 = a a = 5 m/s^2 ACCELERATION

vf = vo +at

vf = 0 + 5m/s^2 (2 s ) = 10 m/s VELOCITY

2 seconds + 90m / 10 m/s = 11 seconds TIME TO FINISH

ElectricPavlov Sep 12, 2019