+234 The first meters of a 100 meter dash are covered in 2 seconds. The sprinter accelerated from rest with a constant acceleration. The remaining 90 m are with the sprinters velocity after the the 2 seconds.
1) what was his acceleration?
for this in class we went over it and talked something about X = Va * t but solving that => 10=Va * 2, The velocuty turns into 5m/s so whats the accelration?
2) find the velocity after the first 2 seconds.
I believe that the answer is 5m/s
3) How long does it take the runner to finish the race.
No idea in notes i just wrote "2s for 10m/s 90m left. 9+2 =11s" Idk where i got the 10m/s from
4) Graph the race
A curve from the origin to 10m and 2s then have a straight line up to 100 and 11s
+36915 Acceleration = change in velocity / change in time
xf = x0 + v0t + 1/2 a t^2 x 0 = 0 v0 = 0 xf=10 x0= original position or start v0 = original velocity at start xf = final position (10m)
10 = 1/2 a (t^2)
10 = 1/2 a (2^2)
20/4 = a a = 5 m/s^2 ACCELERATION
vf = vo +at
vf = 0 + 5m/s^2 (2 s ) = 10 m/s VELOCITY
2 seconds + 90m / 10 m/s = 11 seconds TIME TO FINISH
