How much energy does a 23.0 W light bulb left burning continuously for 336 hr (2 weeks) consume? State your answer in both kilowatt-hours and megajoules.
\(\text{It hopefully is pretty obvious that it uses}\\ \dfrac{23}{1000}\cdot 336~kw\cdot hr\)
\(1~kw\cdot hr = 3.6 \cdot 10^6~J\\ E=\dfrac{23}{1000}\cdot 336 \cdot 3.6 \cdot 10^6 ~J\)
you can do all the calculator work
why did you do 23/1000?
watts to kilowatts
+1438 
