A car on flat ground accelerates at 0.785 m/s^2 when a net force of 1050 N acts on it. How much normal force acts on the car?

Guest May 14, 2019

#1**+3 **

\(F_n = mg\), so let's find the mass

We know the force, \(F\), and the acceleration, \(a\), so we can use \(F = ma\)

\(F = ma \rightarrow 1050 = m(0.785) \rightarrow m = 1337.58 kg\)

Now that we know the mass, we can go back to \(F_n\)

\(F_n = mg \rightarrow F_n = (1337.58)(9.8) \rightarrow F_n = 13108.3 N\)

.Anthrax May 14, 2019