+1995 the screenshot below is from melody , i am reposting this because I have some more questions, however the post is closed.Want to say thank you again to meldoy for helping me ! you have been such a big help.
If melody or anyone who is online can help me answer a few more questions?
The AU i need to use is 1.5 x 10^8 , with that being said, since it is in km wouldnt i need to convert all the values of m from the sun into km? so i can then divide them out by the 1.5 x 10^8 ? to create the linear scale
+129852 Don't know if this helps....but....here's what I did, Jenny.....
I took the log of each AU and plotted these values
For a couple of examples
Mercury - .386 AU ⇒ log (.386) ≈ -.413
Earth - 1 AU ⇒ log (1) = 0
Neptune - 39.5 AU ⇒ log (39.5) ≈ 1.59
Wolf 359 - 492000 ⇒ log (492000) ≈ 5.69
Here is the pic :
+37146 Yes, to convert the meter distnces to AU distances you would need to divide them by 1.5 x 1011 m (which is the AU value in meters ).....the as Cphil shows below, a logarithmic scale would be best to show them on a graph....
