the screenshot below is from melody , i am reposting this because I have some more questions, however the post is closed.Want to say thank you again to meldoy for helping me ! you have been such a big help.

If melody or anyone who is online can help me answer a few more questions?

The AU i need to use is 1.5 x 10^8 , with that being said, since it is in km wouldnt i need to convert all the values of m from the sun into km? so i can then divide them out by the 1.5 x 10^8 ? to create the linear scale

jjennylove Oct 7, 2019

#1**+2 **

Don't know if this helps....but....here's what I did, Jenny.....

I took the log of each AU and plotted these values

For a couple of examples

Mercury - .386 AU ⇒ log (.386) ≈ -.413

Earth - 1 AU ⇒ log (1) = 0

Neptune - 39.5 AU ⇒ log (39.5) ≈ 1.59

Wolf 359 - 492000 ⇒ log (492000) ≈ 5.69

Here is the pic :

CPhill Oct 7, 2019

#2**+2 **

Yes, to convert the meter distnces to AU distances you would need to divide them by 1.5 x 10^{11 }m (which is the AU value in meters ).....the as Cphil shows below, a logarithmic scale would be best to show them on a graph....

ElectricPavlov Oct 7, 2019