We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

the screenshot below is from melody , i am reposting this because I have some more questions, however the post is closed.Want to say thank you again to meldoy for helping me ! you have been such a big help.


If melody or anyone who is online can help me answer a few more questions?


The AU i need to use is 1.5 x 10^8 , with that being said, since it is in km wouldnt i need to convert all the values of m from the sun into km? so i can then divide them out by the 1.5 x 10^8 ? to create the linear scale


 Oct 7, 2019

Don't know if this helps....but....here's what I did, Jenny.....


I took the log  of each AU  and plotted these values


For a couple of examples


Mercury - .386 AU ⇒  log (.386)  ≈ -.413


Earth -  1 AU   ⇒ log (1)  =  0


Neptune - 39.5 AU  ⇒ log (39.5) ≈  1.59


Wolf 359 - 492000 ⇒ log (492000) ≈  5.69


Here is the pic :




cool cool cool

 Oct 7, 2019

Yes, to convert the meter  distnces to AU distances you would need to divide them by 1.5 x 1011 m (which is the AU value in meters ).....the as Cphil shows below, a logarithmic scale would be best to show them on a graph....

 Oct 7, 2019

4 Online Users