A skateboarder is moving 5.25 m/s when he starts to roll up a frictionless hill. How much higher is he when he comes to a stop?
+37146 Yes it is theoretical in that friction is ignored.....but GRAVITY is used in the equation ( the 'g' in 'mgh' )
+165 How many seconds is he rolling? there isn't much information I can use.
+165 Never mind, if you can't tell me that, than what is the incline of the hill?
+37146 Skateboarder's Kinetic Energy = 1/2 mv^2 all of this energy is converted to POTENTIAL ENERGY =mgh (since there is no friction involved)
1/2mv^2 = mgh the m's 'cancel and you are left with:
1/2 v^2 = gh Substitute and solve for 'h'
1/2 (5.25)^2 = 9.81(h)
h= 1.40 meters high
+165 Is that theoretical? Because I know that the incline changes everything, wether or not it's frictionless, that doesn't mean there's no gravity.
+37146 Yes it is theoretical in that friction is ignored.....but GRAVITY is used in the equation ( the 'g' in 'mgh' )
