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Problem on Newton's laws:

An object is hung from a spring balance suspended from the roof of a lift. When the lift is descending with uniform acceleration of \(0.8ms^{-2}\) the balance indicates a weight of 245 N. When the lift is ascending with uniform acceleration \(ams^{-2}\)(to be found) the reading is 294 N.

Find the value of \(a\).

 

The answer is 1.04 \(ms^{-2}\), but can someone please show the method?

 Aug 18, 2021
edited by Guest  Aug 18, 2021
 #1
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In order to get a to be 1.04ms^-2 you have to assume a gravitational acceeration g = 10ms^-2 (rather than the more normal 9.8 or 9.81).

 

 Aug 18, 2021
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Thank you very much!!!
Yes, the book assumes \(g=10ms^{-2}\).

Guest Aug 18, 2021

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