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600
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avatar+1832 

physics
 Nov 30, 2014

Best Answer 

 #7
avatar+33616 
+10

The total energy is constant.  We have enough information at the top to work out what it is.  Everywhere else the total is the same, but the split between kinetic and potential energy is different. At point A we know the potential energy (mgr) so we can use the difference between the known total and the known potential to find the kinetic energy at A ((1/2)mu2).  Hence we can find the velocity (u) at A.  Hence we can find the centrifugal force (mu2/r) at A; this is the only force imposed by the car on the track at this point.

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 Dec 4, 2014
 #1
avatar+1832 
0

I uploded the picture again 

 Dec 2, 2014
 #2
avatar+33616 
+10

Assuming conservation of energy:

 car on track

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 Dec 3, 2014
 #3
avatar+1832 
0

they want the normal force right  ? 

 Dec 3, 2014
 #4
avatar+1832 
0

xvxvxv Dec 3, 2014
 #5
avatar+33616 
+8

As far as I can see the only force that the car applies to the track at point A is the normal force.  

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 Dec 3, 2014
 #6
avatar+1832 
0

well, Now I understood the first part, where you find the mechanical energy at the top 

but why you used it at part B while we need the normal force !  

 Dec 4, 2014
 #7
avatar+33616 
+10
Best Answer

The total energy is constant.  We have enough information at the top to work out what it is.  Everywhere else the total is the same, but the split between kinetic and potential energy is different. At point A we know the potential energy (mgr) so we can use the difference between the known total and the known potential to find the kinetic energy at A ((1/2)mu2).  Hence we can find the velocity (u) at A.  Hence we can find the centrifugal force (mu2/r) at A; this is the only force imposed by the car on the track at this point.

.

Alan Dec 4, 2014
 #8
avatar+1832 
0

nice 

Now I get it 

Thank you 

 Dec 5, 2014

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