Okay, I think I got this one down pact but would like someone to make sure I've done everything correctly and that the answer is correct.
Okay, so here it goes.
If a hammer falls off of a ladder and strikes the ground after 1.5 seconds, how fast will it be travelling (assuming that the acceleration is 9.8 m/s and initial velocity of 0)?
V₂ = V₁ + a∆t
= 0 + (-9.8m/s^2)(1.5s)
= (-15m/s)
Now, if the hammer from above was tossed downward at 4.6m/s from a height of 9.5m above the ground, how high would it be after 0.75s?
∆d = V₁∆t + 1/2a∆t^2
= 4.6(0.75) + 1/2(-9.8)(0.75)^2
= 3.45 + (-4.9)(0.56)
= 3.45 + (-2.74)
= -9.45
So, for the first part the hammer would be travelling (-15m/s) and after 0.75 seconds, the hammer would be(-9.4m). I feel as if this is wrong though.
+39 
