Amy measured the density of copper as 7.2 × 103 kg.m-3. Jamie measured it as 8.1 × 103 kg.m-3. (a) Calculate the percent difference between the two measurements. (b) If the actual density of copper is 8.93 × 103 kg.m-3, calculate the percent error in each of the measurement.
+526 A's measurement = 7.2 × 103 kg/m3
= 7200 kg/m3
J's measurement = 8.1 × 103 kg/m3
= 8100 kg/m3
a) Average of measurements \(={8100+7200 \over 2}\)
\(= 7650\)
⇒ % difference \(={8100-7200 \over 7650}×100\)
\(=11.76\)%
b) Actual density of Cu = 8.93 × 103 kg/m3
= 8930 kg/m3
Now, % error in A's \(={8930-7200 \over 8930}×100\)
\(=19.4\)%
% error in J's \(={8930-8100 \over 8930}×100\)
\(=9.3\)%
Hope you got it. Thanks.
