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Amy measured the density of copper as 7.2 × 103 kg.m-3. Jamie measured it as 8.1 × 103 kg.m-3. (a) Calculate the percent difference between the two measurements. (b) If the actual density of copper is 8.93 × 103 kg.m-3, calculate the percent error in each of the measurement.

 
 Jun 11, 2021
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A's measurement = 7.2 × 10kg/m3

                             = 7200 kg/m3

J's measurement = 8.1 × 103 kg/m3

                            = 8100 kg/m3

 

a) Average of measurements \(={8100+7200 \over 2}\)

                                               \(= 7650\)

 

⇒ % difference \(={8100-7200 \over 7650}×100\)

                          \(=11.76\)%

 

b) Actual density of Cu = 8.93 × 103 kg/m3

                                     = 8930 kg/m3

 

Now, % error in A's \(={8930-7200 \over 8930}×100\)

                               \(=19.4\)%

 

% error in J's \(={8930-8100 \over 8930}×100\)

                      \(=9.3\)%

 

 

Hope you got it. Thanks. 

 
 Jun 11, 2021

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