a car travels 90 meters due north in 15 seconds. then the car turns around and travels 40 meters due south in 5 seconds. what is the magnitude of the average velocity of the car during this 20 second interval
+23251 a car travels 90 meters due north in 15 seconds. then the car turns around and travels 40 meters due south in 5 seconds. what is the magnitude of the average velocity of the car during this 20 second interval
My analysis is different (although maybe not correct):
Since the car ended 50 meters due north of the starting point, the car has ended traveling 50 meters north in 20 seconds; thus, 50/20 = 2.5 m/s.
+12530 a car travels 90 meters due north in 15 seconds. then the car turns around and travels 40 meters due south in 5 seconds. what is the magnitude of the average velocity of the car during this 20 second interval
+23251 a car travels 90 meters due north in 15 seconds. then the car turns around and travels 40 meters due south in 5 seconds. what is the magnitude of the average velocity of the car during this 20 second interval
My analysis is different (although maybe not correct):
Since the car ended 50 meters due north of the starting point, the car has ended traveling 50 meters north in 20 seconds; thus, 50/20 = 2.5 m/s.
+37084 A couple of ways (and answers) to look at this
toatl distance travelled = 90 + 40 = 130 m
total time = 20 s 130/20 = 6.5 m/s avg
If you are looking at how far away the car got from the starting point (using vectors)
90 - 40 = 50 meters from start and it took 20 seconds 50/20 = 2.5 m/s avg
