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The cadmium isotope 109Cd has a half-life of 462 days. A sample begins with 1.0×1012109Cd atoms. How many are left after (a) 29 days, (b) 850 days, and (c) 5400 days?
 Feb 6, 2014
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The cadmium isotope 109Cd has a half-life of 462 days. A sample begins with 1.0×1012109Cd atoms. How many are left after (a) 29 days, (b) 850 days, and (c) 5400 days?



You know that radioactive decay is a decaying exponential function of the form

I(t) = I 0e -at, here t is in days, and a is a rate constant to be solved for given the half life.

Half life means the time until half of the original radioactive atoms are present. So let t h be the half life. Then

1/2 I 0 = I 0 e -ath

1/2 = e -ath

ln(1/2) = -a t h

a = -ln(1/2)/t h = -ln(1/2)/462

Now that you have a you can just plug in the time to answer questions a-c
 Feb 6, 2014

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