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A diverging mirror has a center of curvature of 15 cm. A 3.5-cm object is placed 5.0 cm in front of a mirror. What is the height of the image in centimeters? Answer with two signficant digits.


What is the answer to this?
I've gotten 10.5 cm, and 5.9 cm. The website says the answer is 2.1, but they spelled "significant" wrong, so I don't know whether I'm wrong, or it's wrong. Use all of the usual mirror equations, like f=R/2, etc. Google the rest. I cant type the subscrips and stuff.
 Mar 6, 2014
 #1
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*BUMP*
 Mar 6, 2014
 #2
avatar+118667 
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I can't help you with your question but I can hlep with your presentation.

I am trying really hard to get people to use the 'sup' button which is located just above the smilies.
It makes it much easier to read your questions and answers. It also cuts down on misinterpretation of your questions.
If you want to enter x^2, it is better written as x 2.
To do this you enter x then you hit the 'sup' button, the curser will automatically move to where you need to enter 2.
Once the 2 is there just move your curser to the end and keep going. It is quite quick when you get used to it.

The sub button is very similar.

I will put out a lantern to attract people to your question.
 Mar 7, 2014
 #3
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10.5 is right

ho = height of object
do = distance of object from mirror
c = curvature
fl = focal length = c/2

di = distance the image appears from mirror
hi = height of image

1/do + 1/di = 1/f

(1/do)-(1/f) = -1/di
di = -(do fl)/(f - do)

hi = -(di/do)ho

you can plug the numbers in to see that hi is 10.5
 Mar 7, 2014
 #4
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Thank you guys. Very nice community you got going here. I appreciate your help. You're here for me when my teachers arent


Think I'll register now. You won me over
 Mar 7, 2014
 #5
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Not quite sure how I got 5.9, but when I actually tried, I got 10.5 cm, 3 times in a row. I'll notify my instructor, although, I'm in DAEP, which isn't for the 'smart' ones, so I doubt college physics is a popular class here. lol.
 Mar 7, 2014
 #6
avatar+118667 
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idkman:

Thank you guys. Very nice community you got going here. I appreciate your help. You're here for me when my teachers arent
Think I'll register now. You won me over



Hi idkman,
Welcome to web2.0calc forum. We hope that you like it here.
I am really glad that Rom could help you.
Melody.
 Mar 8, 2014

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