+129847 Vf = Vi + (-9.8m/s^2) t where Vf is the final velocity, Vi is the initial velcocity, -9.8m/s^2 is the acceleration due to gravity, and t is the time.......note......Vi = 0, since the penny is dropped....so we have
Vf = -9.8 (4.5) ≈ -44.1 m/s [ we need the negative because the object is moving in a downward direction ]
The velocity of falling objects is expressed by this equation: v = g * t, where v=terminal velocity, g=acceleration due to gravity, which is 9.81 m/sec^2, t=time in seconds. So, your penny will have a terminal velocity of: v=9.81 X 4.5=44.145m/sec., ignoring air resistance.
+129847 Vf = Vi + (-9.8m/s^2) t where Vf is the final velocity, Vi is the initial velcocity, -9.8m/s^2 is the acceleration due to gravity, and t is the time.......note......Vi = 0, since the penny is dropped....so we have
Vf = -9.8 (4.5) ≈ -44.1 m/s [ we need the negative because the object is moving in a downward direction ]
