Let
\[f(x) = \left\{ \begin{array}{cl} -x - 3 & \text{if } x \le 1, \\ \frac{x}{2} + 1 & \text{if } x > 1. \end{array} \right.\]
Find the sum of all values of $x$ such that $f(x) = 0$
.
-x - 3 = 0 x/2 + 1 = 0
-x = 3 x/2 = -1
x = -3 x = -2
The first value of x is in the domain of - x - 3
The second value of x is NOT in the domainn of x/2 + 1
So .....
-3