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Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit can be repeated in an integer?

 Jul 21, 2020
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Since the digits can be repeated, you will simply have: 4^4 / 2^4 = 16 2-digit permutations as follows:

 

{2, 2} | {2, 4} | {2, 6} | {2, 7} | {4, 2} | {4, 4} | {4, 6} | {4, 7} | {6, 2} | {6, 4} | {6, 6} | {6, 7} | {7, 2} | {7, 4} | {7, 6} | {7, 7} (total: 16)

 Jul 21, 2020

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