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Jeri finds a pile of money with at least $\$200$. If she puts $\$50$ of the pile in her left pocket, gives away $\frac23$ of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away $\$200$ of the original pile and kept the rest. What are the possible values of the number of dollars in the original pile of money? (Give your answer as an interval.)

 

(This question has been posted many times but the many times were all wrong)

 Apr 25, 2021
 #1
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n = original pile

n - (2/3(n - 50)) + 50 >  n - 200

This simplifies to n < 425

 

Answer is [200,425).

 Apr 25, 2021
 #2
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That is wrong

Guest Apr 25, 2021
 #3
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X -200 = 50 + 1/3(x-50)

3X -600 = x + 100

2x = 700

X = 350

 

(350, infinity)

 Apr 25, 2021

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