(5√5)^(-2x + 1) = (1/5) * 125^(x - 3)
We can write
(5^(3/2)) ^(-2x + 1) = (1/5) (5^3)^(x - 3)
5 ^ ( - 3x + 3/2) = (5^-1) ( 5)^(3x - 9)
5^( -3x + 3/2) = 5^( -1 + 3x - 9) we have the same bases.....solve for the exponents
-3x + 3/2 = - 1 + 3x - 9
-3x + 3/2 = -10 + 3x
6x = 10 + 3/2
6x = 11.5
x = 11.5 / 6 = 23 / 12
So....CORRECT!!!!