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avatar+829 

please explain to me how come the graph/shape isnt moved to the left side as the equation is negative

https://snag.gy/4AwGSV.jpg

 Jan 6, 2018

Best Answer 

 #1
avatar+7354 
+2

There is the point  (0, 3)  on  y = f(x) ....  So we know that   f(0)  =  3  .

 

To produce the same  y  value on  y = f(x - 3) , we must input an  x  value such that  x - 3  = 0 .

 

When  x = 3 ,  y  =  f(x - 3)  =  f(3 - 3)  =  f(0)  =  3  ...So on  y = f(x - 3)  there is the point  (3, 3) .

 

At every point, the  x  value in  y = f(x - 3)  must be  3  greater than the  x  value in  y = f(x)  in order for both functions to produce the same  y  value.

 Jan 6, 2018
 #1
avatar+7354 
+2
Best Answer

There is the point  (0, 3)  on  y = f(x) ....  So we know that   f(0)  =  3  .

 

To produce the same  y  value on  y = f(x - 3) , we must input an  x  value such that  x - 3  = 0 .

 

When  x = 3 ,  y  =  f(x - 3)  =  f(3 - 3)  =  f(0)  =  3  ...So on  y = f(x - 3)  there is the point  (3, 3) .

 

At every point, the  x  value in  y = f(x - 3)  must be  3  greater than the  x  value in  y = f(x)  in order for both functions to produce the same  y  value.

hectictar Jan 6, 2018

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