Let ABCD be a trapezoid with bases \(\overline{AB}\) and \(\overline{CD}\). Let AD=5 and BC=7, and let P be a point on side \(\overline{CD}\) such that \(\frac{CP}{PD}=\frac{7}{5}\). Let X,Y be the feet of the altitudes from P to \(\overline{AD}\), \(\overline{BC}\) respectively. Show that PX=PY.
+636 Please do not discuss this problem! This is an active homework problem.
I realize that homework may be challenging. If you wish to receive some help from the staff or other students, I encourage you to use the resources that the online classes provide, such as the Message Board. Thanks.
