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Happy April Fools day guys!! Any way I need help with a math problem....can anyone help?

 

27

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m        So this is basically 27 over m to the fifth power, but it is also all square rooted (idk how to do that)

Guest Apr 1, 2017
 #1
avatar+67 
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sqrt(27)/sqrt(m2) = sqrt(27)/m2*sqrt(m)

basically: Square root of 27 divided by m squared times the square root of m

LithianNerd  Apr 1, 2017
 #2
avatar+67 
+1

I just figured out how to use LaTeX! So it's:

\(\frac{\sqrt{27}}{m^{2}*\sqrt{m}}\)

LithianNerd  Apr 1, 2017
 #3
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Also, you can simplify √27:

 

√27 = √9•3 = 3√3

Guest Apr 1, 2017

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