Happy April Fools day guys!! Any way I need help with a math problem....can anyone help?

27

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m^{5 } So this is basically 27 over m to the fifth power, but it is also all square rooted (idk how to do that)

Guest Apr 1, 2017

#1**+1 **

sqrt(27)/sqrt(m^{2}) = sqrt(27)/m^{2}*sqrt(m)

basically: Square root of 27 divided by m squared times the square root of m

LithianNerd
Apr 1, 2017

#2**+1 **

I just figured out how to use LaTeX! So it's:

\(\frac{\sqrt{27}}{m^{2}*\sqrt{m}}\)

LithianNerd
Apr 1, 2017