Happy April Fools day guys!! Any way I need help with a math problem....can anyone help?
27
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m5 So this is basically 27 over m to the fifth power, but it is also all square rooted (idk how to do that)
+79 sqrt(27)/sqrt(m2) = sqrt(27)/m2*sqrt(m)
basically: Square root of 27 divided by m squared times the square root of m
+79 I just figured out how to use LaTeX! So it's:
\(\frac{\sqrt{27}}{m^{2}*\sqrt{m}}\)
