D is on side AB of Triangle ABC. We know triangle ABC\(\sim\)triangle ACD and angle A=48. If BC=BD, what is angle B in degrees?
here is the image:
I'll add the pic - Melody
I get 28 degrees. (which I have not checked)
Let's see what catmg comes up with.
I really miss going on this forum more often.
Sadly, school is quite busy.
You are the one who did the nice work Catmg.
Yes school is busy, so is life for younger people.
Most of the people who are here a lot, to answer questions I mean, are retired.
It can continue to be a nice hobby for you though :))
It is a very fun hobby.
I quite like working on my math skills and hopefully helping others improve too.
Hello CCeed :))
Let angle B = x
angle A = 48
angle C = 132 - x
Since ABC ~ ACD
angle B = angle ACD = x
angle C = angle CDA = 132 - x
Since BC = BD
BCD = BDC
BCD + BDC + B = 180 degrees
BDC + BDC + x = 180 degrees
BDC = (180-x)/2
CDA + CDB = 180
132 - x + (180-x)/2 = 180
x = 28
I hope this helped. :))
I find it quite difficult to get my head around geometry questions such as this.
So I will give you some insight as to how I go about it.
I drew the diagram and shade the smaller one.
then I said the smallest side of the big triangle is AC which corresponds to the smallest side of the small diagram AD
then I said the biggest side of the big triangle is AB which corresponds to the biggest side of the small diagram AC
Now I draw the corresponding triangles like this:
And then I take it from there.
I suppose it is too slow long term but while you are getting the hang of it it can help.