+1443 Which of the following in simplest factored form is equivalent to: \(12(1-x^2)\)
a) \(-12(1-x) (1+x)\)
b) \(-12(x^2-1)\)
c) \(-12(x-1) (x+1)\)
d) \(12(x-1) (1-x)\)
This is quite easy, let us factor out a -1 from the $(-x^2+1)$, which is $-1(x^2-1)$, we then make this into difference of squares $12*-(x+1)(x-1)$, which results in
$\boxed{-12(x+1)(x-1)}$
+1443 Thank you! I wasn't sure how to switch the numbers around or if I should at all.
