+1443 Which of the following in simplest factored form is equivalent to: 12(1−x2)
a) −12(1−x)(1+x)
b) −12(x2−1)
c) −12(x−1)(x+1)
d) 12(x−1)(1−x)
This is quite easy, let us factor out a -1 from the $(-x^2+1)$, which is $-1(x^2-1)$, we then make this into difference of squares $12*-(x+1)(x-1)$, which results in
$\boxed{-12(x+1)(x-1)}$
+1443 Thank you! I wasn't sure how to switch the numbers around or if I should at all.
