Two cars leave the same location traveling in opposite directions. One car leaves at 3:00 p.m. traveling at an average rate of 55 miles per hour. The other car leaves at 4:00 p.m. traveling at an average rate of 75 miles per hour. Let x represent the number of hours after the first car leaves.
How many hours after the first car leaves will the two cars be 380 miles apart?
Enter an equation that can be used to solve this problem
Solve for x and enter the number of hours
Which inequality models this problem?
Jason started a hat-making business. He spent $750 to purchase supplies to get started and he uses about $3.50 worth of supplies per hat made. Jason charges $15 for each hat. Let h represent the number of hats.
What is the minimum number of hats Jason will need to sell to make a profit?
-15h<750+3.5h
-15h>750+3.5h
-3.5h≥750+15h
-3.5h>750+15h
The formula for the average of two numbers is m= a+b/2
Solve for a.
A photographer offers a photo shoot for a $85 flat fee. Customers may purchase prints for $5 per sheet.
How many sheets can a customer purchase and spend at most $150?
What linear inequality with variable x represents this situation?
What is the solution to that inequality? Enter the solution as an inequality using x.
+130081 Two cars leave the same location traveling in opposite directions. One car leaves at 3:00 p.m. traveling at an average rate of 55 miles per hour. The other car leaves at 4:00 p.m. traveling at an average rate of 75 miles per hour. Let x represent the number of hours after the first car leaves.
How many hours after the first car leaves will the two cars be 380 miles apart?
We want to find this : distance traveled by first car + distance traveled bt second car = 380
And distance = rate * time
So...the first car travels x hours and the second car travels one hour less = x - 1
And we have
55x + 75(x - 1) = 380 simplify
55x + 75x - 75 = 380 add 75 to both sides
130x = 455 divide both sides by 130
x = 3.5 hrs
Jason started a hat-making business. He spent $750 to purchase supplies to get started and he uses about $3.50 worth of supplies per hat made. Jason charges $15 for each hat. Let h represent the number of hats.
What is the minimum number of hats Jason will need to sell to make a profit?
He will make a profit when Sales > Costs ...so
15h > 750 + 3.50h subtract 3.50h from both sides
11.5h > 750 divide both sides by 11.5
h > ≈ 66 hats
m = [ a + b] / 2 multiply both sides by 2
2m = a + b subtract b from both sides
2m - b = a
That's all I have time for....!!!!
+130081 Last one :
A photographer offers a photo shoot for a $85 flat fee. Customers may purchase prints for $5 per sheet.
How many sheets can a customer purchase and spend at most $150?
What linear inequality with variable x represents this situation?
What is the solution to that inequality? Enter the solution as an inequality using x.
For the first one....we have this inequality
85 + 5x ≤ 150 where x is the number of sheets
Subtract 85 from both sides
5x ≤ 65
Divide both sides by 5
x ≤ 13 .....so the customer can by 13 sheets at most
