+2448 Ehh I guess. I'm thinking it would be this for the max. height: -120/2(-16) which equals 3.75 so it would be [0,3.75] and then I got the rest :P i'll show my work if anyone wants me to.
+129852 h(t) = -16t^2 + 120t + 6
The time to reach the max height = -120 /[ 2 * -16 ] = -120 / -32 = 3.75 sec
And....to find the max height, plug this value back into the function =
-16(3.75)^2 + 120 (3.75) + 6 = 231 ft
Note that the change in height is [231 - 6 ] = 225 ft
So...the average rate of change in height from intial height to max height = [231- 6] / 3.75 =
225 / 3.75 = 60 ft / sec
+129852 Well....two great minds couldn't possibly be incorrect, could they ???
LOL!!!
+2448 Well my mind isn't very great haha, but you're never incorrect, so this must be the correct answer. ^-^
