Very similar to the last one, RP
Get to the form (like we did in the other question )
y = mx + b the slope is m
A perpendicular line will have the slope = -1/m
Example :
4) y = -2x + 4 the slope is -2 = m
The slope of a perpendicular line is -1/m = -1 / (-2) = 1/2
So perpendicular line : y = (1/2)x
(As a tip....when we have a whole number slope, m....write it as m/1....then "flip it" and make it negative to find the slope of the perpendicular line....so ..... -2 = -2/1 = - (1/-2) = 1/2....
When we have a fractional slope....flip it and make it negative to find the slope of the perpendicular line ...so....2/3 = -3/2 )
Can you try the other two, RP??? [ I'll check your answers....if you want ]
I dont really get this one though..I have the slopes
5) y=5/3x-1/3
m=5/3
6) y=1/4x+1/4
m=1/4
OK....you have the correct slope for (5) = 5/3
So...a perpendicular line will have the slope = -3/5
And an equation for a perpendicular line : y = (-3/5)x
For (6)
4y - 1 = - 1x add 1 to both sides
4y = -1x + 1 divide both sides by 4
y = (-1/4)x + 1/4 the slope is (-1/4)
A perpendicular line has the slope = 4/1 = 4
( "Flip" -1/4 = -4/1 .. take the negative of this = - (- 4/1) = 4/1 = 4 )
So....the equation for a perpendicular line is : y = 4x
Hope that makes some sense.....!!!