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Let $a\equiv (3^{-1}+5^{-1}+7^{-1})^{-1}\pmod{11}$. What is the remainder when $a$ is divided by $11$?

 Mar 10, 2021
 #1
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(3 inverse + 5 inverse + 7 inverse) inverse = (4 + 9 + 2) inerse

= 15 inverse

= 3

 Mar 10, 2021
 #2
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Thank you, but the corrrect answer is 10.

 

Can you try this problem?

What is the smallest integer n, greater than 1, such that n^-1 is defined?

Guest Mar 10, 2021

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