+0

0
32
2

Let $a\equiv (3^{-1}+5^{-1}+7^{-1})^{-1}\pmod{11}$. What is the remainder when $a$ is divided by $11$?

Mar 10, 2021

#1
0

(3 inverse + 5 inverse + 7 inverse) inverse = (4 + 9 + 2) inerse

= 15 inverse

= 3

Mar 10, 2021
#2
0

Thank you, but the corrrect answer is 10.

Can you try this problem?

What is the smallest integer n, greater than 1, such that n^-1 is defined?

Guest Mar 10, 2021