+0  
 
+2
103
2
avatar+243 

What non-zero rational number must be placed in the square so that the simplified product of these two binomials is a binomial:\((7t-10)(5t+\Box )\) ? Express your answer as a mixed number.

 Jul 16, 2020
 #1
avatar+21953 
+1

To be a binomial, the answer can have only two terms.

 

It will have a t2 term (because 7t·5t = 35t2) and it will have a constant term because, according to the

directions, you can't use zero in the box.

 

Therefore, the t-term must disappear.

 

Using an 'x' for the term in the box, we have:  (7t - 10)(5t + x)  =  35t2 - 50t + 7xt - 50x.

 

We need to get  -50t + 7xt  to be zero:  -50t + 7xt  =  0

(dividing out the t)                                    -50 + 7x  =  0

                                                                          7x  =  50

                                                                            x  =  7 1/7

 Jul 16, 2020
 #2
avatar+243 
+2

thank you

 Jul 16, 2020

19 Online Users

avatar