+0

0
164
1

(x-1/x^2-16)+(x-4/1-x) got a quiz rn need of help

Guest Jun 21, 2017
Sort:

#1
+78
+1

$$\frac{x-1}{{x}^{2}-16}+\frac{x-4}{1-x}$$

factorise;

$$\frac{x-1}{(x+4)(x-4)}+\frac{x-4}{1-x}$$

times the right hand fraction by $$\frac{(x+4)(x-4)}{(x+4)(x-4)}$$

$$\frac{x-1}{(x+4)(x-4)}+\frac{(x-4)(x+4)(x-4)}{(1-x)(x-4)(x+4)}$$

times the left hand fraction by $$\frac{1-x}{1-x}$$

$$\frac{(x-1)(x-1)}{(x+4)(x-4)(x-1)}+\frac{(x-4)(x+4)(x-4)}{(1-x)(x-4)(x+4)}$$

now that they have the same base we can add them

$$\frac{(x-4)(x+4)(x-4)+(x-1)(x-1)}{(1-x)(x-4)(x+4)}$$

times out the brackets

$$\frac{(x^3-4x^2-16x+64)+(-x^2+2x-1)}{(1-x)(x-4)(x+4)}$$

simplify

$$\frac{x^3-5x^2-14x+63}{(1-x)(x-4)(x+4)}$$

thats as far as it goes im afraid - at least what you wrote

wombat  Jun 21, 2017

### 35 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details