The ratio of the areas of two squares is \(\frac{32}{63}\). After rationalizing the denominator, the ratio of their side lengths can be expressed in the simplified form \(\frac{a\sqrt{b}}{c}\) where a, b, and c are integers. What is the value of the sum \(a+b+c \)?

imdumb Jul 19, 2020

#1**+4 **

First, we need to find the side lengths. Since the side length of a square is the square root of the area, we now know that the two side lengths are

\(\sqrt {32} \text{ and } \sqrt{63}\)

The ratio would now be \(\frac{\sqrt{32}}{\sqrt{63}}\).

Simplifying the square roots, we get \(\frac{4\sqrt 2}{3\sqrt 7}\).

From here, we need to multiply the top and bottom by \(\sqrt 7\) to rationalize the denominator. So, we get

\(\frac{4\sqrt {14}}{21}\)

Now, all you have to do is add a, b, and c. This will give us

\(4 + 14 + 21 = 39\)

ilorty Jul 19, 2020