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If , m+(1/m) = 8 then what is the value of m^2 + (1/m^2)+4 ?

Jun 12, 2021

#1
+524
+2

$$m+{1\over m}=8$$

⇒ $$(m+ {1\over m})^2=64$$

$$m^2+{1\over m^2}+2=64$$

$$m^2+{1\over m^2}=62$$

$$m^2+{1\over m^2}+4 = 66$$

~Hope you got it.

Jun 12, 2021

#1
+524
+2

$$m+{1\over m}=8$$

⇒ $$(m+ {1\over m})^2=64$$

$$m^2+{1\over m^2}+2=64$$

$$m^2+{1\over m^2}=62$$

$$m^2+{1\over m^2}+4 = 66$$

~Hope you got it.

amygdaleon305 Jun 12, 2021