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If , m+(1/m) = 8 then what is the value of m^2 + (1/m^2)+4 ?

Guest Jun 12, 2021

Best Answer

+526

+2

$m+{1\over m}=8$

⇒ $(m+ {1\over m})^2=64$

$m^2+{1\over m^2}+2=64$

$m^2+{1\over m^2}=62$

⇒ $m^2+{1\over m^2}+4 = 66$

~Hope you got it.

amygdaleon305 Jun 12, 2021

1⁺⁰ Answers

+526

+2

Best Answer

$m+{1\over m}=8$

⇒ $(m+ {1\over m})^2=64$

$m^2+{1\over m^2}+2=64$

$m^2+{1\over m^2}=62$

⇒ $m^2+{1\over m^2}+4 = 66$

~Hope you got it.

amygdaleon305 Jun 12, 2021

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