Different shape not exactly sure how to do this. Two triangles and a square?

RainbowPanda Dec 4, 2018

#1**+1 **

holy trapezoid batman!

Almost.

Break it into the obvious rectangle, and then two triangles on each side result.

Use the fabled distance formula we keep talking about to get the lengths of the various sides you need

to compute the areas.

Rom Dec 4, 2018

#3

#4**+4 **

The area of a triangle is the base times height times one half. Use pythagoras theorem to find the hypotunse of a triangle and add that to the base and height of the triangle to find the perimeter. The area of a square is one of the sides squared (ex: s^2), hence it is why it is called square. The perimeter of a square is one of the sides times 4.

Try these math sites:

https://www.symbolab.com/ (there is some chemistry there)

https://www.mathway.com/Algebra

https://www.desmos.com/calculator

echofire18 Dec 4, 2018

#5**0 **

So which way is easier and faster lol should I split it in half into 2 triangles?

RainbowPanda
Dec 4, 2018

#7**+4 **

There is a formula for all triangles.

https://www.mathwarehouse.com/geometry/triangles/area/herons-formula-triangle-area.php

echofire18
Dec 4, 2018

#8**0 **

To find AREA I'd go two triangles .... BOTH with base 7 one with h = 2 one with h = 2

ElectricPavlov
Dec 4, 2018

#12**0 **

I am sure you know how to find the area of a triangle ....right? This figure is TWO triangles....add them together to find the total area.....c'mon.....don't make this more difficult than it really is....

ElectricPavlov Dec 4, 2018

#13**0 **

I'm sorry i'm not as smart as you. I do know how to find the area of a triangle but I haven't even gotten the perimeter yet. Also you said 2 triangles and that is 4.

RainbowPanda
Dec 5, 2018

#14**0 **

Higher up in this thread I posted how to find the area of a triangle....

there is actually only TWO triangles of concern in the scan I posted......the lines marked 'H' are just to show the dimensions for 'Height'...... You CAN do it...... And you don't need the perimeter to calculate the area....(though I do understand you have to find the perimeter per the question)

ElectricPavlov
Dec 5, 2018

#15**0 **

I didn't mean to sound rude, I'm just super stressed right now. Problem is I don't know the height or base of the triangles.

Would one triangle be 1/2*6*2

and the other 1/2*6*4 or am I completely wrong

RainbowPanda
Dec 5, 2018

#18**0 **

This scan may be a bit clearer..... Cowgirl Up ! as they say....don't stress...you can do this.....I am not going to do it for you, but I'll help you through it........it will become easier as YOU work tyour way through it.....go !

ElectricPavlov Dec 5, 2018

#21**0 **

So how exactly do I do this, I got the area which is 21 and now how do i get the perimeter

AB

DA

DC

and CB?

RainbowPanda
Dec 5, 2018

#20**0 **

Exactly ! 7 Now you can calculate the areas of both of the triangles (1/2 b * h ) then add them together....

Voila ! You have the area of the composite figure.......

Now let's start work on the perimeter.....

Distance between two points on the coordinate plane d^2 = (x1-x2)^2 + (y1-y^2)^2 (remember?)

You might have to do it FOUR times for this figure.... Go!

ElectricPavlov Dec 5, 2018

#22**+1 **

Is the perimeter 19

Oh my god im literally crying and freaking out rn because I CANT FREAKING GET THIS IM SO FREAKING STU PID!!!!!!!!!!!!!!

RainbowPanda
Dec 5, 2018

#23**0 **

Learning is sometimes difficult....But all of a sudden it will go "CLICK" !. Hang in there..

I'll show you how to do the first part of the perimeter....I'll do the longest side

two points (x1 y1) and (x2 y2) are (-1,5) and (5,1) right?

Use the formula: d^2 = (x1-x2)^2 + (y1-y2)^2

= (-1-5)^2 + (5-1)^2

d^2 = (-6)^2 + (4)^2

d^2 = 36 + 16

d^2 = 52

d= sqrt(52) = 7.21 units (for ONE side of the perimeter)

See how I did that? Now you do it for the opposite side (3,7) and (-1,5) Then we will be half way....

try it and let me know what you get.....

ElectricPavlov
Dec 5, 2018

#24**0 **

I get 19.41 for the total perimeter (sorry didn't see that in your last post).....

ElectricPavlov Dec 5, 2018