Different shape not exactly sure how to do this. Two triangles and a square?
holy trapezoid batman!
Break it into the obvious rectangle, and then two triangles on each side result.
Use the fabled distance formula we keep talking about to get the lengths of the various sides you need
to compute the areas.
...or break it in to two triangles area of triangle = 1/2 base x height
The area of a triangle is the base times height times one half. Use pythagoras theorem to find the hypotunse of a triangle and add that to the base and height of the triangle to find the perimeter. The area of a square is one of the sides squared (ex: s^2), hence it is why it is called square. The perimeter of a square is one of the sides times 4.
Try these math sites:
https://www.symbolab.com/ (there is some chemistry there)
So which way is easier and faster lol should I split it in half into 2 triangles?
Careful.... Pythagorean Theorem only works for RIGT triangles !
There is a formula for all triangles.
To find AREA I'd go two triangles .... BOTH with base 7 one with h = 2 one with h = 2
You should keep it as ONE shape because a quadrilateral is very simple.
I am sure you know how to find the area of a triangle ....right? This figure is TWO triangles....add them together to find the total area.....c'mon.....don't make this more difficult than it really is....
I'm sorry i'm not as smart as you. I do know how to find the area of a triangle but I haven't even gotten the perimeter yet. Also you said 2 triangles and that is 4.
Higher up in this thread I posted how to find the area of a triangle....
there is actually only TWO triangles of concern in the scan I posted......the lines marked 'H' are just to show the dimensions for 'Height'...... You CAN do it...... And you don't need the perimeter to calculate the area....(though I do understand you have to find the perimeter per the question)
I didn't mean to sound rude, I'm just super stressed right now. Problem is I don't know the height or base of the triangles.
Would one triangle be 1/2*6*2
and the other 1/2*6*4 or am I completely wrong
This scan may be a bit clearer..... Cowgirl Up ! as they say....don't stress...you can do this.....I am not going to do it for you, but I'll help you through it........it will become easier as YOU work tyour way through it.....go !
Exactly ! 7 Now you can calculate the areas of both of the triangles (1/2 b * h ) then add them together....
Voila ! You have the area of the composite figure.......
Now let's start work on the perimeter.....
Distance between two points on the coordinate plane d^2 = (x1-x2)^2 + (y1-y^2)^2 (remember?)
You might have to do it FOUR times for this figure.... Go!
Is the perimeter 19
Oh my god im literally crying and freaking out rn because I CANT FREAKING GET THIS IM SO FREAKING STU PID!!!!!!!!!!!!!!
Learning is sometimes difficult....But all of a sudden it will go "CLICK" !. Hang in there..
I'll show you how to do the first part of the perimeter....I'll do the longest side
two points (x1 y1) and (x2 y2) are (-1,5) and (5,1) right?
Use the formula: d^2 = (x1-x2)^2 + (y1-y2)^2
= (-1-5)^2 + (5-1)^2
d^2 = (-6)^2 + (4)^2
d^2 = 36 + 16
d^2 = 52
d= sqrt(52) = 7.21 units (for ONE side of the perimeter)
See how I did that? Now you do it for the opposite side (3,7) and (-1,5) Then we will be half way....
try it and let me know what you get.....