Line 1 represents the graph of 3x + 4y = -14. Line 2 passes through the point (-5,7), and is perpendicular to line 1. If line 2 represents the graph of y=mx +b, then find m+b.
We write Line 1 in slope intercept form.
3x+4y=-14
4y=-3y-14
y=-3/4x-14/4
The slope of line 2 must be 4/3. So we currently have y=4/3x+b. We plug in the given point (-5, 7) to find b.
y=4/3x+b
7=4/3(-5)+b
7=-20/3+b
b=41/3.
The equation of line 2 is y=4/3x+41/3. m is 4/3 and b is 41/3. Therefore m+b=4/3+41/3=45/3=15.